Bitwise Operators and Byte to Bit Conversion

# include "stdio.h"
# include "string.h"

const char* byte_to_binary( int x );
int main()
{

    int nInput=0, nOutput=2, nBitPos;

    // To set the bit in particular position.
    nInput |= (1 << nOutput);
    printf("To set the %d Position from 1bit of %s\n",nOutput, byte_to_binary(nInput));

    // To Reset/Clear the bit in particular position.
    nInput &= ~(1 << nOutput);
    printf("To Reset/Clear the %d Position from 1bit of %s\n",nOutput, byte_to_binary(nInput));

    // To toggle the bit in particular position.
    nInput =5; // 00000101 expected like 00000001
    nInput ^= (1 << nOutput);
    printf("To toggle the %d Position from 1bit of %s\n",nOutput, byte_to_binary(nInput));

    // To state of the bit in particular position.
    nInput =5; // 00000101 expected like 00000101
    nBitPos = nInput &(1 << nOutput);
    printf("To state of the %d Position from 1bit of %s:: state of bit: %d\n",nOutput, byte_to_binary(nInput), nBitPos);


return 0;
}



//To Byte to Binary Conversion
const char* byte_to_binary( int x )
{
    static char b[9] = {0};
    int z, y;

    for (z=128,y=0; z>0; z>>=1,y++)
    {
        b[y] = ( ((x & z) == z) ? '1' : '0');
    }

    b[y] = 0;

    return b;
}



Output:
To set the 2 Position from 1bit of 00000100
To Reset/Clear the 2 Position from 1bit of 00000000
To toggle the 2 Position from 1bit of 00000001
To state of the 2 Position from 1bit of 00000101:: state of bit: 4

binary format display

#include "stdio.h"
int a, b, c, d, e;
void main()
{
int i;
a = 65;
b = 0x41;
c = 'A';
d = 'A'+3;

printf("a = %d b = %d c = %d\n", a, b, c);

printf("Ascii %c, decimal %d, hex %02x\n", d, d, d);

printf("Here is d in binary: ");
for(i = 7; i>=0; i--) {
if((1<<i)&d)
printf("1");
else
printf("0");
}
printf("\n");
}